Hi @chrdttchavan ,



One way of linearizing this is to use binary variables. I would recommend you to create a set Ranges (with index r) - each element in this set corresponds to the different steps/ranges you have for x.



Set

Ranges := data{Range-1, Range-2, Range-3}.



Parameters,



LowerLimit(r) := {1, 3, 5};

UpperLimit(r) := {3, 4, 6};

MultiplicationFactor(r) := {a, b, c};.



BinaryVariable(r).



Now have the following constraints.



Constraint_1

y = sum[r, BinaryVariable(r)*MultiplicationFactor(r)]



Constraint_2

sum[r, BinaryVariable(r)] = 1



Constraint_3(r)

x >= BinaryVariable(r) * LowerLimit(r)



Constraint_4(r)



X <= (1-BinaryVariable(r))*M + UpperLimit(r)



Here, M is a sufficiently large positive number. You can use M = 10 for your case.



You are essentially using BinaryVariable(r) to track in which range does the value of x lie in, and based on the value of BinaryVariable(r), you can calculate the value of y.

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Hi @chrdttchavan did this help solve your problem? Or did you find another way? It may help others to know. Thanks 🙂

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